TASK 1
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Assumptions :1. The 2 men are opposite sides of the building and that the width of the building is negligible.
2. The 2 men's eye level is at the base of the building.
3. The building is perpendicular to the ground.
Solution:
tan60º=120/x
x= 120/tan60º
= 69.3m (3s.f.)
tan30º=120/y
y=120/tan30º
= 208m (3s.f.)
Distance between the 2 men = 69.3m+208m=277m(3s.f.) OR 208m-69.3m=139m (3s.f.)
TASK 2
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SINE RULE
COSINE RULE
TASK 3
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A. Amplitude is the angle between the real axis of an Argand diagram and a vector representing a complex number.
B. Wavelength is the distance between successive crests of a wave, esp. points in a sound wave or electromagnetic wave.
C. Frequency is the number of waves occurring in 1 second.
D. Phase is the relationship in time between the successive states or cycles of an oscillating or repeating system and either a fixed reference point or the states or cycles of another system with which it may or may not be in synchrony.
E. Characteristics of the waveIt is described using the wavelength, Phase, period, frequency and amplitude of the wave
Transformation 1: y=3sin(x)
Transformation 2: y=sin(2x)
Transformation 4: y=sin(x)+3
Transformation 3: y=sin(90-x)
Are the two men looking at the same point at the top of the same building?
ReplyDeleteYou've assumed that the 2 men are at opposite sides of the building. This means you are not looking at the other possibility that the 2 men are on the same side of the building. If that is so, why are there 2 solutions to the question?
Is assuming that the width of the building is negligible practical?
Did you also assume that the ground was completely flat?
What do X and Y represent?
Other than these slight problems, your working is quite clear, and your solutions are accurate.
-Group 3 (Kashyap, Bowen, Hao Xian, Darryl, Jerome)
As mentioned in other groups as well, Good to consider other cases and eventually decide on the best possible solution.
ReplyDeletegood analysis but a visual representation will certainly aid learning.